The parameter inequality of the halting verifier #
Blueprint lem:lambda-bound (ledger node 1.6.4): for all C, C' ≥ 1, all
λ ≥ 4 · max ((4C) ^ (8C)) (C · log₂ C') and all n ≥ 2,
C · (C' · λ · n) ^ C ≤ n ^ λ.
This is the arithmetic that makes a λ-boundedness accounting go through. Every verifier the
pipeline produces has running times polynomial in the level and in λ — poly(n, λ), the
shape MIPRE.GapCompression.decider_time and sampler_time state — while
MIPRE.Verifier.IsBounded λ asks for n ^ λ. The inequality says that once λ is large
enough in terms of the polynomial's degree alone, the second dominates the first at every
level n ≥ 2; and λ large enough is what blueprint lem:lambda chooses. C is the degree
and C' the coefficient, so the threshold is exponential in the degree and only logarithmic in
the coefficient — which is what keeps λ polynomial in the description length rather than
exponential in it.
log is Nat.log 2 throughout, so the hypothesis is the integer reading of the blueprint's;
nothing below needs it to be the real logarithm, and reading it as Nat.log 2 makes the
threshold no larger.
The proof is the obvious one made finite. Bound each factor of the left-hand side by a power of
n — C' ≤ 2 ^ (log₂ C' + 1) and λ ≤ 2 ^ (log₂ λ + 1) and C ≤ 2 ^ C, with 2 ≤ n — so
that the claim reduces to the linear statement 4C + C · log₂ C' + C · log₂ λ ≤ λ. Two of
those three terms are a quarter of λ by hypothesis outright. The third,
C · log₂ λ ≤ λ / 4, is the only one with content: it is λ < 2 ^ (λ / (4C)), which holds
once λ / (4C) exceeds 8C + 4, because 2 ^ q overtakes q ^ 2 at q = 4
(Nat.sq_le_two_pow_of_four_le) and q ^ 2 ≥ q · (8C + 4) > 4C · (q + 1) there.
Two facts about powers of two #
The parameter inequality #
Blueprint lem:lambda-bound. For C, C' ≥ 1, every
λ ≥ 4 · max ((4C) ^ (8C)) (C · log₂ C') and every n ≥ 2,
C · (C' · λ · n) ^ C ≤ n ^ λ.
The threshold is exponential in the degree C and logarithmic in the coefficient C'.
The blueprint also asks C' ≥ 1; the proof does not need it (C' < 2 ^ (log₂ C' + 1) holds at
C' = 0 too), so it is not a hypothesis here. Dropping it only strengthens the statement.